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ABCD is a trapezium such that AB and CD are parallel and BC perpendicular on CD.If angle ADB=θ, BC =p and CD=q, then AB is equal to A)p 2 + q 2 cos θ/pcosθ+qsinθ ​B) p 2 + q 2 /p 2 cos θ+q 2 sin θ C)(p 2 + q 2 )sin θ/(pcos θ+qsin θ) 2 D) (p 2 + q 2 )sin θ/(pcos θ+qsin θ)

ABCD is a trapezium such that AB and CD are parallel and BC perpendicular on CD.If angle ADB=θ, BC =p and CD=q, then AB is equal to
A)p2 + q2 cos θ/pcosθ+qsinθ
​B)p2 + q2/p2cosθ+q2sinθ
C)(p2 + q2 )sinθ/(pcosθ+qsinθ)2
D)(p2 + q)sinθ/(pcosθ+qsinθ)

Grade:11

2 Answers

neha
18 Points
7 years ago
b
Pooja
20 Points
4 years ago
I think D is the correct answer to this question ..........................,..........................

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