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IN TRIANGLE ABC CotA : Cot B : Cot C = 30;16;9, FIND THE RATIO a;b;c = what is the ratio
dear frnd!!!
u first get it into sin and cos !! and after den u can apply the sine formula :) :)
In a Triangle
Cot A*Cot B + Cot B*CotC + Cot C*Cot A = 1
Now, Cot A/30=Cot B/16=Cot C/9 = x (say)
put it above
x^2*(30*16+16*9+9*30) = 1
x^2 = 1/894
x = y(say)
therefore , Cot A = 5/y , Cot B = 16/y , Cot C = 9/y
now get ,
sin A = (1+cot A^2)^1/2
sin B = (1+cot B^2)^1/2
sin C = (1+cot C^2)^1/2
required ratio .
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