Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

prove that 1/cos 290+1/root 3.sin 250=4/root 3

prove that 1/cos 290+1/root 3.sin 250=4/root 3

Grade:11

3 Answers

Sunil Raikwar
askIITians Faculty 45 Points
7 years ago
1/cos290+1/root3.sin250
=1/sin20 -1/root3.cos20
=root3cos20-sin20/root3.sin20.cos20
=4.(sin60co20-cos60sin20)/root3.2sin20cos20 [multiply and divide by 4]
=4sin40/root3.sin40= 4/root3
Thanks & Regards
Sunil Raikwar
askIITians Faculty
Jatin
26 Points
3 years ago
=1/sin20 -1/root3.cos20=root3cos20-sin20/root3.sin20.cos20=4.(sin60co20-cos60sin20)/root3.2sin20cos20 [multiply and divide by 4]=4sin40/root3.sin40= 4/root3
christo
15 Points
10 months ago
cos(290)=cos(270+20)=sin20
sin(250)=sin(270-20)= -cos20
therefore,1/cos290+1/root3.sin250=1/sin20-1/root3.cos20
=root3.cos20-sin20/root3.sin20*cos20 (by cross multiplying)
=2(root3/2cos20-1/2sin20)/(1/2*root3.2sin20cos20)    (2sin20.cos20=sin40)
=2(sin60.cos20-cos60.sin20)/(1/2*root3.sin40)    (sin60.cos20-cos60*sin20=sin40)
=4sin40/root3.sin40=4/roo3
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free