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tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ]=tan[tan-1a +tan-1a]=tan(2tan-1a)=2a/(1-a2)
Dear Nelwin Jacob,
tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ] = tan[tan-1a +tan-1a]=tan(2tan-1a)=2a/(1-a2)
Hope this helped you immensely...
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AskIITians Expert,
Godfrey Classic Prince
IIT-Madras
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