Flag Trigonometry> Inverse Circular functions...
question mark

tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ]

Nelwin Jacob , 13 Years ago
Grade 11
anser 2 Answers
Chetan Mandayam Nayakar

Last Activity: 13 Years ago

tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ]=tan[tan-1a +tan-1a]=tan(2tan-1a)=2a/(1-a2)

Godfrey Classic Prince

Last Activity: 13 Years ago

Dear Nelwin Jacob,

tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ] = tan[tan-1a +tan-1a]=tan(2tan-1a)=2a/(1-a2)

 

Hope this helped you immensely...

All the Very Best & Good Luck to you ...

Regards,

AskIITians Expert,

Godfrey Classic Prince

IIT-Madras

Please approve my answer if you liked it by clicking on "Yes" given below...!!Smile

star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments