tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ]

tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ]=tan[tan^-1a +tan^-1a]=tan(2tan^-1a)=2a/(1-a²)

Dear Nelwin Jacob,

tan[ 1/2 sin^-1 (2a/1+a^2) + 1/2 cos^-1 (1-a^2/1+a^2) ] = tan[tan^-1a +tan^-1a]=tan(2tan^-1a)=2a/(1-a²)

Hope this helped you immensely...

All the Very Best & Good Luck to you ...

Regards,

AskIITians Expert,

Godfrey Classic Prince

IIT-Madras

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