Flag Trigonometry> Where did I go wrong?...
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I can't find where I went wrong!! Can anybody please find it for me?

We already have:

tan(Π-x)=-tan(x); --(1)

and

tan(-x)=-tan(x); --(2)

So we start:

Let x = tan-1(-y),

Then -y = tan(x);

=> y = -tan(x);

=> y = tan(Π-X) and y = tan(-x) using (1) and (2)

=> Π-x=tan-1(y) and -x= tan-1(y)

=> -x = tan-1(y)-Π and -x = tan-1(y)

=> x = Π - tan-1(y) and x = -tan-1(y)

=> Π - tan-1(y) = - tan-1(y)

=> Π = 0

How can it be possible? Where I went wrong??

Please help me!

Davis Devasia , 14 Years ago
Grade 12
anser 2 Answers
SAGAR SINGH - IIT DELHI

Last Activity: 14 Years ago

Dear student,

Please go thru Inverse trignometric  functions, There are some coditions when inverse of a function is applied.....

Davis Devasia

Last Activity: 14 Years ago

Can you please note it here? I couldn't find where I am wrong!

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