Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
What is the value of Cos(2Cos-1x+Sin-1x) at x=1/5?
cos-1x + sin-1x = pi/2 ............1 (identity)
cos(2cos-1x+sin-1x) = cos[(cos-1x+sin-1x) + cos-1x]
=cos[pi/2 + cos-1x] (by using eq 1)
( we know , cos[pi/2+A] = -sinA )
=-sin[cos-1x]
=-sin[sin-1(1-x2)1/2] (cos-1x = sin-1(1-x2)1/2 )
=-(1-x2)1/2
at x = 1/5
=-(2root6)/5
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !