Trigonometry> solution of triangles...
If the incircle of the triangle ABC passes through its circumcentre, then prove that cosA
+cosB+cosC = √2
1 Answers
Last Activity: 15 Years ago
Dear student,
The circle passing through the vertices of the triangle ABC is called the circum-circle. Its radius R is called the circum-radius. In the triangle
ABC, R = a/2 sin A = b/2 sin B = c/ 2 sin C = abc/4Δ.
From here we can deduce that
cosA+cosB+cosC = √2
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