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Prove that sin2nx+ cos2nx ≤ 1 for all x and n≥1

manoj jangra , 14 Years ago
Grade 12
anser 1 Answers
bibhash jha

Last Activity: 14 Years ago

Dear Manoj,

 

0<=sin^2(x) ,cos^2(x)<=1 for all x

therefore , sin^2n(x) <=sin^2x and cos^2n(x)<=cos^2(x) for n>=1

 

adding both we get  sin2nx +  cos2nx ≤ 1

 

 

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