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sin(37) ???

sin(37) ???

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12 Answers

Sona Srivastava
38 Points
13 years ago

in a right angled triangle with sides as 3,4,5 or 6,8,10 the angles other than the right angle are 37° and 53° 
so

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

fgdgd
13 Points
7 years ago
fgfdg\sum \prod \Cap \setminus \lozenge \blacklozenge \blacksquare \triangle \triangleleft \gamma \varpi \mu \nu \iota \kappa \eta \zeta \omega \phi \sigma
utpal raj
238 Points
7 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
this is very important for exam point of view so remember this …
good luck
 
llol
11 Points
7 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
is correct so do some revision on this\!!!!!!!!!!!!!!!!!!!!!
Prince Zrk
26 Points
7 years ago
Remember cos as father Cos 53 =5/3 just oppositeAnd sin is reverse so 5/3=sin 37And one value is 4/5 So cos37and sin53 is for thatThanks
Aman sharma
11 Points
7 years ago
Exact value of sin37° & cos37° areSin37°=0.601Cos37°=0.798°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
Karthi
13 Points
6 years ago
Its very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90`,53` and 37` now by using sin and cos thita ratios we can find the angles that isSin37`= opposite / hypotaneus = 3/5Similarly :Sin53`= 4/5Cos37` = 3/5cos53`= 3/5
HJHJHJHJH
14 Points
6 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
it is so simle
 
HJHJHJHJH
14 Points
6 years ago
 
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
it is so simple 
srry for the mistake
 
Chetana
11 Points
6 years ago
 
It’s very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90`,53` and 37` now by using sin and cos thita ratios we can find the angles sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
Monalisha Nayak
13 Points
5 years ago
It's so simple
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
A very good luck for exams
Rishi Sharma
askIITians Faculty 646 Points
3 years ago
Hello students,
The solution of the above problem is attached.
I hope the solution will solve all your doubts.
Being a standerd pythogorus triplet it is advisable to remember the angles and sides to enhance your speed in exams.
Thank You,
All the Best for the Exams.

645-1110_WhatsApp Image 2020-06-05 at 1.41.15 AM.jpeg

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