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# sin(37) ???

Sona Srivastava
38 Points
11 years ago

in a right angled triangle with sides as 3,4,5 or 6,8,10 the angles other than the right angle are 37° and 53°
so

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

fgdgd
13 Points
4 years ago
$fgfdg\sum \prod \Cap \setminus \lozenge \blacklozenge \blacksquare \triangle \triangleleft \gamma \varpi \mu \nu \iota \kappa \eta \zeta \omega \phi \sigma$
utpal raj
244 Points
4 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
this is very important for exam point of view so remember this …
good luck

llol
11 Points
4 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
is correct so do some revision on this\!!!!!!!!!!!!!!!!!!!!!
Prince Zrk
26 Points
4 years ago
Remember cos as father Cos 53 =5/3 just oppositeAnd sin is reverse so 5/3=sin 37And one value is 4/5 So cos37and sin53 is for thatThanks
Aman sharma
11 Points
4 years ago
Exact value of sin37° & cos37° areSin37°=0.601Cos37°=0.798°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
Karthi
13 Points
4 years ago
Its very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90,53 and 37 now by using sin and cos thita ratios we can find the angles that isSin37= opposite / hypotaneus = 3/5Similarly :Sin53= 4/5Cos37 = 3/5cos53= 3/5
HJHJHJHJH
14 Points
4 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
it is so simle

HJHJHJHJH
14 Points
4 years ago

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
it is so simple
srry for the mistake

Chetana
11 Points
4 years ago

It’s very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90,53 and 37 now by using sin and cos thita ratios we can find the angles sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
Monalisha Nayak
13 Points
2 years ago
It's so simple
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
A very good luck for exams
Rishi Sharma
one year ago
Hello students,
The solution of the above problem is attached.
I hope the solution will solve all your doubts.
Being a standerd pythogorus triplet it is advisable to remember the angles and sides to enhance your speed in exams.
Thank You,
All the Best for the Exams.