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# sin(37) ???

11 years ago

in a right angled triangle with sides as 3,4,5 or 6,8,10 the angles other than the right angle are 37° and 53°
so

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°

4 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
this is very important for exam point of view so remember this …
good luck

4 years ago
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
is correct so do some revision on this\!!!!!!!!!!!!!!!!!!!!!
4 years ago
Remember cos as father Cos 53 =5/3 just oppositeAnd sin is reverse so 5/3=sin 37And one value is 4/5 So cos37and sin53 is for thatThanks
4 years ago
Exact value of sin37° & cos37° areSin37°=0.601Cos37°=0.798°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°
4 years ago
Its very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90,53 and 37 now by using sin and cos thita ratios we can find the angles that isSin37= opposite / hypotaneus = 3/5Similarly :Sin53= 4/5Cos37 = 3/5cos53= 3/5
4 years ago

sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
it is so simple
srry for the mistake

4 years ago

It’s very simple construct a triangle sides 3,4,5 and mark the angle thita now one angle will be 90,53 and 37 now by using sin and cos thita ratios we can find the angles sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
2 years ago
It's so simple
sin37° = 3/5 = cos53°
sin53° = 4/5 = cos37°
tan37° = 3/4 = cot53°
tan53° = 4/3 = cot37°
A very good luck for exams
one year ago
Hello students,
The solution of the above problem is attached.
I hope the solution will solve all your doubts.
Being a standerd pythogorus triplet it is advisable to remember the angles and sides to enhance your speed in exams.
Thank You,
All the Best for the Exams. 