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Grade: 12
        
(1+i)^5+(1-i)^5 what is the value of this question if i =^-1
 
 
10 months ago

Answers : (4)

Arun
20865 Points
							
Dear Nasir
You can use binomial theorem
even terms will cancel out
besides there are many ways in whoch it can be solved easily but at this moment no other metod is reminding to me
 
Regards
Arun (askIITians forum expert)
10 months ago
Yuvraj singh
11 Points
							
You can use exponential form of complex numbers to solve it.They are conjugates.Thus the calculation reduces.
10 months ago
Aditya Gupta
1124 Points
							
using binomial theorem we can expand it to obtain the final answer as 
 – 8
note that
i^1=i
i^2= – 1
i^3= – i
i^4= 1
i^5 = i
and so on
8 months ago
Subham Patel
29 Points
							Dear student,(1+i)^5 + (1-i)^5(1+I)(1+I)^4 + ( 1-i)(1-i)^4(1+i)(1+i^2 +2i)^2 + (1-i)(1+i^2 -2i)^2(1+i)(2i)^2 + (1-i)(-2i)^24i^2(1+i) + 4i^2(1-i)Now we know i^2=-1-4(1+i) - 4(1-i)-4-4i-4+4i-4-4= -8 is the answer ..I hope it will help u .you can easily solve this question by property of complex number . .Regards...Subham
						
one month ago
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