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```
(1+i)^5+(1-i)^5 what is the value of this question if i =^-1

```
2 years ago

Arun
25768 Points
```							Dear NasirYou can use binomial theoremeven terms will cancel outbesides there are many ways in whoch it can be solved easily but at this moment no other metod is reminding to me RegardsArun (askIITians forum expert)
```
2 years ago
Yuvraj singh
11 Points
```							You can use exponential form of complex numbers to solve it.They are conjugates.Thus the calculation reduces.
```
2 years ago
2074 Points
```							using binomial theorem we can expand it to obtain the final answer as  – 8note thati^1=ii^2= – 1i^3= – ii^4= 1i^5 = iand so on
```
2 years ago
Subham Patel
29 Points
```							Dear student,(1+i)^5 + (1-i)^5(1+I)(1+I)^4 + ( 1-i)(1-i)^4(1+i)(1+i^2 +2i)^2 + (1-i)(1+i^2 -2i)^2(1+i)(2i)^2 + (1-i)(-2i)^24i^2(1+i) + 4i^2(1-i)Now we know i^2=-1-4(1+i) - 4(1-i)-4-4i-4+4i-4-4= -8 is the answer ..I hope it will help u .you can easily solve this question by property of complex number . .Regards...Subham
```
one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions