(1+cotA+tanA)(sina-cosa)/sec ^3a-cosec ^ 3a=sin ^ 2A.cos ^ 2A prove that
Mrunmay More , 9 Years ago
Grade 10
Trigonometry> (1+cotA+tanA)(sina-cosa)/sec ^3a-cosec ^ ...
2 AnswersHarsh Patodia
PFA
Aaranys
LhsDenominator:(secA-cosecA)(sec^2+cosec^2A+secAcosecA)={(1+cosA/sinA+sinA/cosA) (sinA-cosA)}/(1/cosA -1/sinA)(1/cos^2A+1/sin^2A+1/sinAcosA){(SinAcosA +1/sinAcosA ) (sinA-cosA)}/(sinA-cosA/sinAcosA)(1+SinAcosA/cos^2Asin^A)(1+SinAcosA)(sinA-cosA)(sinAcosA)(sin^2A cos^2A)/(sinAcosA)(sinA-cosA)(1+sinAcosA)=sin^2Acos^A=RhsLhs=RhsHence Proved
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