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X liters of carbonmonoxide is present at STP.It is completely oxidized to co2.The volume of co2 formed is 11.207liters at STP.what is the value of X in liters?
The balanced cheical rection is:CO + 1/2O2 --------------> CO2 moles = 11.207/22.4 = > 1.9735 moles of CO = is also, 1.9735 from mole – 1 analysis.Hence volume at STP for CO is:1.9735 = X/22.4that is same as = > 11.207 litre.Hence the same Volume will be oxidized.
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