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Which one of the following reactions is a redox reaction? (a) C u S O 4 ​ + 4 N H 3 ​ → C u ( N H 3 ​ ) 4 ​ ] S O 4 ​ (b) N a 2 ​ S O 4 ​ + B a C l 2 ​ → B a S O 4 ​ + 2 N a C l (c) S O 2 ​ + H 2 ​ O → H 2 ​ S O 3 ​ (d) 2 C u S O 4 ​ + 4 K I → C u 2 ​ I 2 ​ + 2 K 2 ​ S O 4 ​ + I 2 ​ .

Which one of the following reactions is a redox reaction?
(a) CuSO4​+4NH3​→Cu(NH3​)4​]SO4​
(b) Na2​SO4​+BaCl2​→BaSO4​+2NaCl
(c) SO2​+H2​O→H2​SO3​
(d) 2CuSO4​+4KI→Cu2​I2​+2K2​SO4​+I2​.

Grade:8

2 Answers

Vikas TU
14149 Points
3 years ago
Dear student 
In Option D 
Oxidation number of Cu decreases from +2 to +1 and oxidation number of iodine increases from −1 to 0.
So, D is Cortrect Choice.
ankit singh
askIITians Faculty 614 Points
3 years ago

The reaction in which change in oxidation numbers of some of the atoms takes place is termed as a redox reaction.
(a) CuSO4​+2+6−2​+4NH3​−3+1​→[Cu+2(N−3H3​+1​)4​]S+6O4​−2​
No change in oxidation number of any of the atoms.
(b) Na2​+1​S+6O4​−2​+Ba+2Cl2​−1​→Ba+2S+6O4​−2​+2Na+1Cl−1
No change in oxidation number of any one of the atoms.
(c) S+4O2​−2​+H2​+1​O−2→H2​+1​S+4O3​−2​
No change in oxidation number of any one of the atoms.
(d) 2Cu+2S+6O4​−2​+4K+1I−1→Cu2​+1​I2​−1​+2K2​+1​S+6O4​−2​+I2​0​.
Oxidation number of Cu decreases from +2 to +1 and oxidation number of iodine increases from −1 to 0.
Thus, out of the above four reactions, the reaction (d) is a redox reaction.

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