Which is a stronger reducing agent Cr2+ or Fe2+ and why ?
rishav kumar , 12 Years ago
Grade 9
Physical Chemistry> Which is a stronger reducing agent Cr2+ o...
3 Answers
Sumit Majumdar
Dear student,
There are two reason for Cr3+ to be more reducing than Fe2+:
The electrode reduction potential values are:
The electrode reduction potential values are:
As we know that, the more negative the electrode potential greater is the reducing power of the electrode.
The highest oxidation state for Cr is +6, therefore it can loose 3 more electrons, whereas Fe needs to loose only 1 electron to achieve its highest oxidation state of +3. Thus, Cr3+ is more reducing than Fe2+.
The highest oxidation state for Cr is +6, therefore it can loose 3 more electrons, whereas Fe needs to loose only 1 electron to achieve its highest oxidation state of +3. Thus, Cr3+ is more reducing than Fe2+.
Regards
Sumit
Rahul
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Yash Chourasiya
Dear Student
Cr2+ is a stronger reducing agent than Fe2+.
This can be explained on the basis of the standard electrode potential values E°(Cr3+/Cr2+ = –0.41 V) and E° (Fe3+/Fe2+ = + 0.77 V).
Thus Cr2+ is easily oxidised to Cr3+but Fe2+ cannot be as readily oxidised to Fe3+.
I hope this answer will help you.
Thanks & Regards
Yash Chourasiya
Cr2+ is a stronger reducing agent than Fe2+.
This can be explained on the basis of the standard electrode potential values E°(Cr3+/Cr2+ = –0.41 V) and E° (Fe3+/Fe2+ = + 0.77 V).
Thus Cr2+ is easily oxidised to Cr3+but Fe2+ cannot be as readily oxidised to Fe3+.
I hope this answer will help you.
Thanks & Regards
Yash Chourasiya
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