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```
When an electric current is passed through acidulated water 112ml of hydrogen gas at step collects at the cathode in 965sec. The current passed in ampere is?

```
2 years ago

Khimraj
3007 Points
```							mole of hydrogen = 112/22400 = 1/200 = 0.005charge required = 0.005*96500  = 482.5 CTHENI*t = 482.5I*965 = 482.5So I = 0.5AHope it clears. If you like answer then please approve it.
```
2 years ago
ANISHA GHOSH
13 Points
```							2H2O+ 2e-  → H2 + 2OH-no. of moles=112/22400=1/200 mol Q=(1/200)*96500*2         (As 2 electrons are involved)we know,It=Q=> I*965 = 965=> I = 1Ahope i cleared ur doubt...
```
one year ago
13 Points
```							The first answer is wrong. For 1mole hydrogen 2F is needed...that is 2×96500So .005 mole requires .005×2×96500C=965CQ=ItI=Q÷t =965÷965=1Ampere
```
one year ago
610 Points
```							Dear student,Please find the attached answer to your problem below. 2H2O+ 2e-  → H2 + 2OH-no. of moles=112/22400=1/200 molQ=(1/200)*96500*2         (As 2 electrons are involved)we know,I = Q/t=> I = 965/965=> I = 1A Hope it helps.Thanks and regards,Kushagra
```
6 months ago
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