0

Guest

Courses New

When an electric current is passed through acidulated water 112ml of hydrogen gas at step collects at the cathode in 965sec. The current passed in ampere is?

When an electric current is passed through acidulated water 112ml of hydrogen gas at step collects at the cathode in 965sec. The current passed in ampere is?

Grade:12

4 Answers

Khimraj
3007 Points
5 years ago
mole of hydrogen = 112/22400 = 1/200 = 0.005
charge required = 0.005*96500  = 482.5 C
THEN
I*t = 482.5
I*965 = 482.5
So I = 0.5A
Hope it clears. If you like answer then please approve it.
ANISHA GHOSH
13 Points
5 years ago
2H2O+ 2e-  → H2 + 2OH-
no. of moles=112/22400=1/200 mol 
Q=(1/200)*96500*2         (As 2 electrons are involved)
we know,
It=Q
=> I*965 = 965
=> I = 1A
hope i cleared ur doubt...
 
Badarunissa
13 Points
5 years ago
The first answer is wrong. For 1mole hydrogen 2F is needed...that is 2×96500
So .005 mole requires .005×2×96500C
=965C
Q=It
I=Q÷t
 =965÷965=1Ampere
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the attached answer to your problem below.
 
2H2O+ 2e-  → H2 + 2OH-
no. of moles=112/22400=1/200 mol
Q=(1/200)*96500*2         (As 2 electrons are involved)
we know,
I = Q/t
=> I = 965/965
=> I = 1A
 
Hope it helps.
Thanks and regards,
Kushagra

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More