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Grade: 12
        
When an electric current is passed through acidulated water 112ml of hydrogen gas at step collects at the cathode in 965sec. The current passed in ampere is?
11 months ago

Answers : (3)

Khimraj
2873 Points
							
mole of hydrogen = 112/22400 = 1/200 = 0.005
charge required = 0.005*96500  = 482.5 C
THEN
I*t = 482.5
I*965 = 482.5
So I = 0.5A
Hope it clears. If you like answer then please approve it.
11 months ago
ANISHA GHOSH
13 Points
							
2H2O+ 2e-  → H2 + 2OH-
no. of moles=112/22400=1/200 mol 
Q=(1/200)*96500*2         (As 2 electrons are involved)
we know,
It=Q
=> I*965 = 965
=> I = 1A
hope i cleared ur doubt...
 
3 months ago
Badarunissa
13 Points
							
The first answer is wrong. For 1mole hydrogen 2F is needed...that is 2×96500
So .005 mole requires .005×2×96500C
=965C
Q=It
I=Q÷t
 =965÷965=1Ampere
2 months ago
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