When alcohol and acetic acid are mixed together in equimolecular proportions,66.5% are converted into ester.Calculate the equilibrium constant of the reaction.

Question

Vikas TU · Answer

If 66.5% is converted into ester then the remaining proportion => 33.5%. Hence in equimolar the proportion would be after eqm reached would be => 33.5/2 % each. Hence, K = 66.5/(33.5/2)^2 = 0.23702

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When alcohol and acetic acid are mixed together in equimolecular proportions,66.5% are converted into ester.Calculate the equilibrium constant of the reaction.

When alcohol and acetic acid are mixed together in equimolecular proportions,66.5% are converted into ester.Calculate the equilibrium constant of the reaction.

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When alcohol and acetic acid are mixed together in equimolecular proportions,66.5% are converted into ester.Calculate the equilibrium constant of the reaction.

When alcohol and acetic acid are mixed together in equimolecular proportions,66.5% are converted into ester.Calculate the equilibrium constant of the reaction.

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