When 2 moles of C 2 H 6 are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔH f for C 2 H 6 ; Δ H f for CO 2 and H 2 O are -395 and -286 KJ respectively

Question

When 2 moles of C 2 H 6 are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔH f for C 2 H 6 ; Δ H f for CO 2 ­ and H 2 O are -395 and -286 KJ respectively

Arun · Answer

Dear student Total heat energy=395+286+3129 = 3810 Hope it helps In case of any difficulty, please feel free to ask.

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When 2 moles of C 2 H 6 are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔH f for C 2 H 6 ; Δ H f for CO 2 and H 2 O are -395 and -286 KJ respectively

When 2 moles of C₂H₆ are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔH_f for C₂H₆; ΔH_f for CO₂ and H₂O are -395 and -286 KJ respectively

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When 2 moles of C 2 H 6 are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔH f for C 2 H 6 ; Δ H f for CO 2 ­ and H 2 O are -395 and -286 KJ respectively

When 2 moles of C2H6 are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔHf for C2H6; ΔHf for CO2­ and H2O are -395 and -286 KJ respectively

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When 2 moles of C 2 H 6 are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔH f for C 2 H 6 ; Δ H f for CO 2 and H 2 O are -395 and -286 KJ respectively

When 2 moles of C₂H₆ are completely burnt 3129 KJ of heat is liberated. Calculate the heat of formation, ΔH_f for C₂H₆; ΔH_f for CO₂ and H₂O are -395 and -286 KJ respectively