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what will be the relation between rate constant k 1 and k 2 of a first order reaction when temperature changes from 280 K to 300 K and activation energy is zero?

aditya kashyap , 12 Years ago
Grade upto college level
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Askiitians Tutor Team

When considering the relationship between the rate constants \( k_1 \) and \( k_2 \) of a first-order reaction as the temperature changes from 280 K to 300 K, particularly with an activation energy of zero, we can derive some interesting insights. In this scenario, the rate constants are influenced primarily by temperature, but since the activation energy is zero, the situation simplifies significantly.

Understanding Rate Constants and Temperature

The rate constant \( k \) for a reaction is often described by the Arrhenius equation, which is given by:

k = A e^(-Ea/RT)

In this equation:

  • A is the pre-exponential factor, a constant that represents the frequency of collisions and the orientation of reactants.
  • Ea is the activation energy.
  • R is the universal gas constant (8.314 J/(mol·K)).
  • T is the temperature in Kelvin.

When the activation energy \( Ea \) is zero, the equation simplifies to:

k = A

Implications of Zero Activation Energy

With \( Ea = 0 \), the rate constant \( k \) becomes independent of temperature. This means that regardless of the temperature change from 280 K to 300 K, the rate constant will remain constant:

k_1 = k_2 = A

Temperature Change and Its Effect

Even though we are increasing the temperature, the absence of activation energy means that the energy barrier for the reaction is nonexistent. Therefore, the reaction can proceed at the same rate regardless of the temperature change. This is quite different from reactions with positive activation energy, where an increase in temperature typically results in an increase in the rate constant due to more molecules having sufficient energy to overcome the energy barrier.

Practical Example

Imagine a scenario where you have a simple chemical reaction, such as the decomposition of hydrogen peroxide into water and oxygen. If this reaction had an activation energy of zero, it would proceed at the same rate whether it was at room temperature or in a hot environment. Thus, if you measured the rate constants at both temperatures, you would find:

k_1 (at 280 K) = k_2 (at 300 K)

Final Thoughts

In summary, for a first-order reaction with zero activation energy, the rate constants \( k_1 \) and \( k_2 \) at temperatures of 280 K and 300 K will be equal. This highlights the unique nature of reactions that do not require energy input to proceed, allowing them to maintain consistent rates across a range of temperatures.

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