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        what is the value of orbital angular momentum of 6s orbital ?
one year ago

Guneet Singh
24 Points
							The value of orbital angular momentum of an electron in an orbital is independent of its principal quatum number. For any electron, the orbital angular momentum is given by the expression {l ( l + 1)} ^ 0.5  * n*h/2*pi  So, for the electron in the 6s orbital, the required value is (0 * 1)^0.5 *  n*h/2*pi = 0 kg m^2 s^-1

one year ago
SRC Jayanth
57 Points
							The orbital angular momentum can be given as $\frac{\displaystyle \sqrt{l(l+1)}h}{2\pi }$for s orbital l=0by substituting orbital angular momentum = 0

one year ago
Mridul Mohan Bagri
12 Points
							The original Angular Momentum of a orbital is given by the formula L=√l(l+1)h/2πSo for s orbital the Angular Momentum Quantum Number(l) is 0.Therefore the Orbital Angular Momentum is zero

one year ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions