What is the (OH)- ion in the solution prepared by mixing 20 ml of .050 M HCl with 30ml of .10 M. Ba(OH)2?

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Vikas TU · Answer

moles of OH- in BaOH2 initially is: = > 30 * 1/10 = > 3*2 = 6 mm moles of H+ => 1 mm i mm of OH- react with one mm of H+. remaining mm of OH- => 6 – 1 = 5 mm. ccn. = 5 x 10^-3 / 0.05 = 0.1 M

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What is the (OH)- ion in the solution prepared by mixing 20 ml of .050 M HCl with 30ml of .10 M. Ba(OH)2?

What is the (OH)- ion in the solution prepared by mixing 20 ml of .050 M HCl with 30ml of .10 M. Ba(OH)2?

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