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What is the enthalpy change when 3mol of liqili benzene transform to the vapor state at ist boiling point 80degree and at 1bar pressure
Dear student change in enthalpy, dH = dU + pdV= dU + dn*R*TAs the change is occuring at the boiling temperature, dH = 3*R*Tuse T = 273+80=353K.
Dear student You already determined the ΔS for benzene at 353 K by dividing the ΔH at 353 K by the temperature 353 K. Now all you need to do is determine the ΔH at 343 K using Hess' law? Once you do that, you can get the ΔS at 343 K.
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