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Volume of co2 obtained at STP by the complete decompositions of 9.8g Na2Co3 is

Volume of co2 obtained at STP by the complete decompositions of 9.8g Na2Co3 is

Grade:12th pass

2 Answers

Arun
25750 Points
4 years ago
Na2CO3⇒ Na2O + CO2
1 mole of sodium carbonate give 1 mole of carbon dioxide.
as 105.98g sodium carbonate gives 44.01g carbon dioxide
therefore, 9.85 g sodium carbonate gives = 9.85 × 44.01 =4.09 g of CO2 105.98 
Moles of CO2 mole = weight =4.09/44.01= 0.092 mole
Molar mass
1 mole of gas = 22.4 L gas 
Therefore,0.092 mole of CO2 = 22.4 × 0.092 = 2.06 L CO2.
Yashwanth Gowda B D
26 Points
2 years ago
You may get answer as 2.08 L by calculation. But Na2CO3 is a soda ash which does not decomposes on heating 👍

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