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Grade: 12th pass
        
Volume of co2 obtained at STP by the complete decompositions of 9.8g Na2Co3 is
one month ago

Answers : (1)

Arun
22318 Points
							
Na2CO3⇒ Na2O + CO2
1 mole of sodium carbonate give 1 mole of carbon dioxide.
as 105.98g sodium carbonate gives 44.01g carbon dioxide
therefore, 9.85 g sodium carbonate gives 9.85 × 44.01 =4.09 g of CO2 105.98 
Moles of CO2 mole = weight =4.09/44.01= 0.092 mole
Molar mass

1 mole of gas = 22.4 L gas 
Therefore,0.092 mole of CO2 = 22.4 × 0.092 = 2.06 L CO2.
one month ago
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