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`        Volume of co2 obtained at STP by the complete decompositions of 9.8g Na2Co3 is`
6 months ago

Arun
23518 Points
```							Na2CO3⇒ Na2O + CO21 mole of sodium carbonate give 1 mole of carbon dioxide.as 105.98g sodium carbonate gives 44.01g carbon dioxidetherefore, 9.85 g sodium carbonate gives = 9.85 × 44.01 =4.09 g of CO2 105.98 Moles of CO2 mole = weight =4.09/44.01= 0.092 moleMolar mass1 mole of gas = 22.4 L gas Therefore,0.092 mole of CO2 = 22.4 × 0.092 = 2.06 L CO2.
```
6 months ago
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• Test paper with Video Solution
• Mind Map
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• NCERT Solutions
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