Grade 11Physical ChemistryTwo Moles of NH3 gas are introduced into a previously evacuated one litre vessel in which it partially dissociates at high temperature . AT equilibrium one mole of NH3 remain,the value of equilibrium constant Prateek 8 Years agoGrade 11
BIKRAM8 Years ago Reaction: 2NH3 = 3H2 + N2Initial amount(mol) 2 – – Final amount(mol) (2-1) 3 1 =1Equlibrium Constan,K=(1 × 33)/1= 9 unit
Savita Singh7 Years agoRx 2NH3 = N2 + 3H2Initial mole= 2 0 0Final Mole = 1 1/2 3/2 Equilibrium constant = 3/2*3/2*3/2*1/2= 27/16 ans
AVNI AGRAWAL7 Years ago no of moles at t=0 2at t=teq 2-x 3x/2 x/2but as per the question,2-x =1 ---> x = 1thus, 1 3/2 ½ equilibrium constant= [H2]3 × [N2]/[NH3]2substituting values.. we get,equilibrium constant= 33/23 × 1/2=27/16
Kushagra Madhukar5 Years agoDear student,Please find the answer to your question. 2NH3 = N2 + 3H2Initial mole= 2 0 0Final Mole = 1 1/2 3/2 Equilibrium constant = [H2]3 × [N2]/[NH3]2 = (3/2)3 × (1/2) / 12 = 27/16 Thanks and regards,Kushagra