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Grade: 11
        Two Moles of NH3 gas are introduced into a previously evacuated one litre vessel in which it partially dissociates at high temperature . AT equilibrium one mole of NH3 remain,the value of equilibrium constant
one year ago

Answers : (3)

BIKRAM
53 Points
							
              Reaction: 2NH3 = 3H2 + N2
Initial amount(mol)    2          –   –  
Final amount(mol)  (2-1)       3         1
                              =1
Equlibrium Constan,K=(1 × 33)/1= 9 unit
one year ago
Savita Singh
24 Points
							
Rx             2NH3 = N2 + 3H2
Initial mole= 2            0       0
Final Mole = 1           1/2    3/2 
Equilibrium constant = 3/2*3/2*3/2*1/2= 27/16 ans 
      
 
 
 
 
 
5 months ago
AVNI AGRAWAL
14 Points
							
    no of moles                       2NH_{3}\rightleftharpoons 3H_{2} + N_{2}
at t=0                                         2
at t=teq                                     2-x              3x/2        x/2
but as per the question,
2-x =1   ---> x = 1
thus,                                           1                 3/2        ½
 
 
equilibrium constant=     [H2]3 × [N2]/[NH3]2
substituting values.. we get,
equilibrium constant=  33/2 × 1/2=27/16
25 days ago
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