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Grade: 12th pass

                        

The vapour density of N2O4 at certain temperature is 30. Calculate the percentage dissociation of N2O4 at this temperature. N2O4(g) gives 2NO2(g)

The vapour density of N2O4 at certain temperature is 30. Calculate the percentage dissociation of N2O4 at this temperature.
N2O4(g) gives 2NO2(g)

2 years ago

Answers : (2)

Arun
25768 Points
							
N2O4 ---------NO2.        Initially N2O4 has conc.= 1            then at equilibrium N2O4 has conc.1-X. And NO2 has conc. =2x         initially we have taken N2O4 =1 Molar mass =92 .V.D at eq.=30 .M.w.=60.
n initial/ n final =M final/M initial 
1/1-X+2X=60/92
1/1+X=60/92
1+X=92/60
X=92/60 -1 
X=32/60
X=0.53           percentage dissociation=0.53 X 100=53
2 years ago
Anurag kumar
13 Points
							
Consider the total mole =100 initially Let ued be x Then, N2O4-----2NO2 Left(100-x) 2x average mass =2×v.d=2×35=70 So, total mass/total moles=70 =100×92/100-x+2x=70 31.4%
one year ago
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