0

Guest

Courses New

The vapour density of N2O4 at certain temperature is 30. Calculate the percentage dissociation of N2O4 at this temperature. N2O4(g) gives 2NO2(g)

The vapour density of N2O4 at certain temperature is 30. Calculate the percentage dissociation of N2O4 at this temperature.
N2O4(g) gives 2NO2(g)

Grade:12th pass

2 Answers

Arun
25750 Points
5 years ago
N2O4 ---------NO2.        Initially N2O4 has conc.= 1            then at equilibrium N2O4 has conc.1-X. And NO2 has conc. =2x         initially we have taken N2O4 =1 Molar mass =92 .V.D at eq.=30 .M.w.=60.
n initial/ n final =M final/M initial 
1/1-X+2X=60/92
1/1+X=60/92
1+X=92/60
X=92/60 -1 
X=32/60
X=0.53           percentage dissociation=0.53 X 100=53
Anurag kumar
13 Points
4 years ago
Consider the total mole =100 initially Let ued be x Then, N2O4-----2NO2 Left(100-x) 2x average mass =2×v.d=2×35=70 So, total mass/total moles=70 =100×92/100-x+2x=70 31.4%

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More