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Grade: 11
        
The value of ∆G•for phosphorylation  of the glucose in the glycolysis is 13.8 Kilo joule per mole find the value of kc  at 298 Kelvin
one year ago

Answers : (1)

Arun
23328 Points
							
ΔG=-2.303RT log Kc
where R =8.314jk^-1mol^-1;T=298k;
Given
ΔG=13.8KJ/Mol but has value of R is in joules,we take it as 13.8×10³j/mol
therefore 13.8×10³=-2.303×8.314×298logKc
log Kc =-2.4185
antilog=0.2661×10^-2
 
one year ago
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