The solubility product of Al(OH)3 and Zn(OH)2 are 8.5× 10^-23 and 1.8 × 10^-14 at room temperature. If the solution contains Al+3 and Zn+2 ions, the ion first precipitated by adding NH4OH is1) Al3+ 2) Zn2+3) both4) none

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Jayendra · Answer

For same conc of al+3 and zn+3 ions the conc of oh- required for precipitation are al3+ = [oh,,-]=( (8.5*10^-23)/c)^1/3 hence aloh3 will be ans

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The solubility product of Al(OH)3 and Zn(OH)2 are 8.5× 10^-23 and 1.8 × 10^-14 at room temperature. If the solution contains Al+3 and Zn+2 ions, the ion first precipitated by adding NH4OH is1) Al3+ 2) Zn2+3) both4) none

The solubility product of Al(OH)3 and Zn(OH)2 are 8.5× 10^-23 and 1.8 × 10^-14 at room temperature. If the solution contains Al+3 and Zn+2 ions, the ion first precipitated by adding NH4OH is1) Al3+ 2) Zn2+3) both4) none

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The solubility product of Al(OH)3 and Zn(OH)2 are 8.5× 10^-23 and 1.8 × 10^-14 at room temperature. If the solution contains Al+3 and Zn+2 ions, the ion first precipitated by adding NH4OH is1) Al3+ 2) Zn2+3) both4) none

The solubility product of Al(OH)3 and Zn(OH)2 are 8.5× 10^-23 and 1.8 × 10^-14 at room temperature. If the solution contains Al+3 and Zn+2 ions, the ion first precipitated by adding NH4OH is1) Al3+ 2) Zn2+3) both4) none

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