Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
THE REACTION BETWEEN GASEOUS NH3 and HBr produces a white solid NH4Br.SUPPOSE a small quantity of gaseous NH3 and gaseous HBr are introduced simultaneously into opposite ends of an open tube which is one metre long . Calculate the distance of white solid formed from the end which was used to introduce NH3. EXPLAIN IT PROPERLY !! I'm in 9th standard ....
Graham's law of Diffusion can be applied Both gases meet at a point to form white solid NH4Br, so time taken by both is same.Length of tube is 1m or 100 cmTake distance travelled by NH3 as x so that by HBr will be 100- x Rate of Diffusion of NH3/ Rate of Diffusion of HBr will be equal to square root of molar mass of HBr by molar mass of NH3 and also equal to distance travelled by NH3 by time divided by distance travelled by HBr by t So final equation comes like Root of molar mass of HBr/Root of molar mass of NH3= x/100-x
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -