Sunil Kumar FP
Last Activity: 10 Years ago
It is given by the formula
log(k2/k1)=Ea/2.303R(1/T1 -1/T2)
log(.07/.02)=Ea/2.303*8.314(1/500-1/700)
Ea=18228kJ
now again we have
k=Ae^(-Ea/RT)
.02=Ae^(-18228/8.314*500)
A=1.6s^-1
The above are the values of Ea and A