The integrated rate law for a first order reaction uses this equation : r=k[A]. But if there are two reactants and the rate law goes like this : r=k[A] 1/2 [B] 1/2 ...the order here as well is 1..so the integrated rate law expression will change right?

Question

Dhulipala Srikanth · Answer

NO BECAUSE RATE INVERSLY PROPORTIONAL TO THE CONCENTRATION OF THE RECNTANT

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The integrated rate law for a first order reaction uses this equation : r=k[A]. But if there are two reactants and the rate law goes like this : r=k[A] 1/2 [B] 1/2 ...the order here as well is 1..so the integrated rate law expression will change right?

The integrated rate law for a first order reaction uses this equation : r=k[A]. But if there are two reactants and the rate law goes like this : r=k[A]^1/2[B]^1/2...the order here as well is 1..so the integrated rate law expression will change right?

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The integrated rate law for a first order reaction uses this equation : r=k[A]. But if there are two reactants and the rate law goes like this : r=k[A] 1/2 [B] 1/2 ...the order here as well is 1..so the integrated rate law expression will change right?

The integrated rate law for a first order reaction uses this equation : r=k[A]. But if there are two reactants and the rate law goes like this : r=k[A]1/2[B]1/2...the order here as well is 1..so the integrated rate law expression will change right?

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The integrated rate law for a first order reaction uses this equation : r=k[A]. But if there are two reactants and the rate law goes like this : r=k[A]^1/2[B]^1/2...the order here as well is 1..so the integrated rate law expression will change right?