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```        The average velocity of an ideal gas molecule at 27°C is 0.3 m/s. The average velocity at 927°C will be
a. 0.6 m/s
b. 0.3 m/s
c. 0.9 m/s
d. 3.0 m/s
```
5 years ago

Navjyot Kalra
654 Points
```							Sol. Expression for average velocity is uavg = √(8RT/πM)
For the same gas but at different temperature
(u_avg 〖(T〗_1) )/(u_avg (T_2 ) )  = √(T_1/T_2 )  = √(300/1200)  =  1/2
⇒ uavg (927°C) = 2 × uavg (27°C) = 0.6 ms-1

```
5 years ago
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