The activation energy for a reaction is 9 kilo calories per mole the increase in rate constant when its temperature is increased from 298 to 300 kelvin is

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Arun · Answer

Dear Prem Use Log k2/k1 = Ea/2.303 R (1/T1 - 1/T2) Then you will find relationship bewtween k2 and k1. Now you can find change

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The activation energy for a reaction is 9 kilo calories per mole the increase in rate constant when its temperature is increased from 298 to 300 kelvin is

The activation energy for a reaction is 9 kilo calories per mole the increase in rate constant when its temperature is increased from 298 to 300 kelvin is

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The activation energy for a reaction is 9 kilo calories per mole the increase in rate constant when its temperature is increased from 298 to 300 kelvin is

The activation energy for a reaction is 9 kilo calories per mole the increase in rate constant when its temperature is increased from 298 to 300 kelvin is

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