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Grade: 12

                        

Tge vapour pressure of methyl alcohol and ethyl alcohol at 25°c are 90 and 40 mm of Hg respectively. If 12 g of CH3OH and 48 g of C2H5OH are mixed, calculte tge vapour pressure exerted by each component, the total vapour pressure of mixture and the composition of mixture.

Tge vapour pressure of methyl alcohol and ethyl alcohol at 25°c are 90 and 40 mm of Hg respectively. If 12 g of CH3OH and 48 g of C2H5OH are mixed, calculte tge vapour pressure exerted by each component, the total vapour pressure of mixture and the composition of mixture.

8 months ago

Answers : (1)

Arun
25768 Points
							
Hello Student,
Please find the answer to your question
Ptotal = pA + pB
Molecular weight of CH3OH = 12 + 3 + 16 + 1 = 32
Molecular weight of C­2H5OH = 24 + 5 + 16 + 1 = 46
According to Raoult’s law
Ptotal = p1 + p2
Where Ptotal = Total vapour pressure of the solution
P1 = Partial vapour pressure of one component
P2 = Partial vapour pressure of other componenet
Again, p1 = Vapour pressure (po1) * mole fraction
Similarly, p2 = Vapour pressure (po2) * mole fraction
Mole fraction of CH3OH = 40/32 /40/32+60/46 = 0.49
Mole fraction of ethanol = 60/46 /60/46+40/32 = 0.51
NOTE THIS STEP : Thus now let us first calculate the partial vapour pressures, i.e., p1 and p2 of the two component.
Partial vapour pressure of CH3OH(p1)
= 44.5 * 0.51 = 22.69 mm
∴ Total vapour pressure of the solution
= 43.48 + 22.69 mm = 66.17 mm
Mole fraction of CH3OH in vapour = 43.48/66.17 = 0.65
 
Thanks and regards
8 months ago
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