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Tge vapour pressure of methyl alcohol and ethyl alcohol at 25°c are 90 and 40 mm of Hg respectively. If 12 g of CH3OH and 48 g of C2H5OH are mixed, calculte tge vapour pressure exerted by each component, the total vapour pressure of mixture and the composition of mixture.
Tge vapour pressure of methyl alcohol and ethyl alcohol at 25°c are 90 and 40 mm of Hg respectively. If 12 g of CH3OH and 48 g of C2H5OH are mixed, calculte tge vapour pressure exerted by each component, the total vapour pressure of mixture and the composition of mixture.

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8 months ago

```							Hello Student,Please find the answer to your questionPtotal = pA + pBMolecular weight of CH3OH = 12 + 3 + 16 + 1 = 32Molecular weight of C­2H5OH = 24 + 5 + 16 + 1 = 46According to Raoult’s lawPtotal = p1 + p2Where Ptotal = Total vapour pressure of the solutionP1 = Partial vapour pressure of one componentP2 = Partial vapour pressure of other componenetAgain, p1 = Vapour pressure (po1) * mole fractionSimilarly, p2 = Vapour pressure (po2) * mole fractionMole fraction of CH3OH = 40/32 /40/32+60/46 = 0.49Mole fraction of ethanol = 60/46 /60/46+40/32 = 0.51NOTE THIS STEP : Thus now let us first calculate the partial vapour pressures, i.e., p1 and p2 of the two component.Partial vapour pressure of CH3OH(p1)= 44.5 * 0.51 = 22.69 mm∴ Total vapour pressure of the solution= 43.48 + 22.69 mm = 66.17 mmMole fraction of CH3OH in vapour = 43.48/66.17 = 0.65 Thanks and regards
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8 months ago
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