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As the rate constant is -
r = k[A]^n
By the info given in Q we can judge that the value of “n” or order is 0.5 as -
r = k[A]^n…. (1)
2r = k[4A]^n…. (2)
Dividing eqn 1 and 2 -
1/2 = (1/4)^n
Implies n=0.5
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