Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state?

Question

Sumit Majumdar · Answer

Dear student,

The asnwer isCerium (Z = 58)

The reason being:When a particular oxidation state become less sable relative to other oxidation states, one
lower. One higher, it is said to undergo disproportionation.

Regards

Sumit

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Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state?

Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state?

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Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state?

Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state?

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