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```
N2+3h2=2nh3 I mol of nitrogen and 4 mol of hydrogen are taken in 15l flask at27°c after complete conversion of n2to nh3 5 l of h 2o is added pressure in flask?

```
4 years ago

```							N2+3h2=2nh3Here N2 is the limiting Reagent.Therefore, moles of NH3 is=> 1*2 => 2 moles.Now H2O is added,Hence the reacn. becomes,NH3  +   H2O  --------------->        NH4OH2 mol                                           2 mol.Hence Total pressure in flask woould be,P*15 = 2*R*300P = 600R/15 => 40R atm      or => 40 * 0.0821 => 3.284 atm.
```
4 years ago
```							Here, 2 moles of NH3 is formed and 1 mole of H2 is leftover.Also, since 5 litre of water is added, Vol=10L.P= (1*0.0821*300)/10=2.463atm
```
one year ago
```							N2+3h2=2nh3Here N2 is the limiting Reagent. 5lit of water is added so volume gets used ,so available space is 15 -5 =10 lit   ammonia (gas) which has presssure ,but when water is added it gets converted to nh4oh solution (liq)   NH3  +   H2O  --------------->        NH4OH   initial               1mol(LR)           4mol          0mol                            N2                   +   3h2       =   2nh3final                 0 mol                   8/3mol       2 mol     total no of moles after complete conversion is 8/3  nh3 is used up by water   preeesure in flask is =nrt/v                                   =8/3*0.0821*300//  10                                   =3.284atm     total no of moles
```
5 months ago
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