Maximum no. of electrons are present in

1.2.24 lit of SO₂ at N.T.P.

2.0.2 moles of NH₃

3.1.5gm atoms of oxygen

4.2 gm atoms of sulphur

Please give me the detail solution of my question!

(i) 1 molecule of SO2 contains 28 electrons.

1 mole (22.4 L) of SO2 contains 6.023 x 1023 molecules of SO2.

Thus, 22.4 L of SO2 contains (6.023 x 1023 x 28) = 1.68 x 1025 electrons.

(ii) 1 molecule of NH3 contains 10 electrons.

1 mole of NH3 contains 6.023 x 1023 molecules of NH3.

Thus, 0.2 mole of NH3 contains (6.023 x 1023 x 10 x 0.2) = 1.205 x 1024 electrons.

(iii) 1 molecule of O2 contains 12 electrons.

1 mole (1 gram mole) of O2 contains 6.023 x 1023 molecules of O2.

Thus, 1.5 gram mole of O2 contains (6.023 x 1023 x 12 x 1.5) = 1.084 x 1025 electrons.

(iv) 1 atom of S contains 16 electrons.

1 mole atom of S contains 6.023 x 1023 atoms of S.

Thus, 2 mole atom of S contains (6.023 x 1023 x 16 x 2) = 1.927 x 1025 electrons.

Therefore, 2 mole atom of S contains the highest number of electrons.