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```
Ksp of Mg(OH)2 IS 4*10^-12 .the no. of moles of Mg2+ ions in one litre of its saturated solution in 0.1 M NaOH is??

```
one year ago

Arun
25141 Points
```							Ksp = [Mg2+] [OH¯]2Let the concentration of Mg2+ ions to form saturated solution be s mol/litre4 x 10-12 = s x (0.1)2 s = 4 x 10-10 mol/litreVolume of solution = 1 litre Number of moles of Mg2+ = Molarity x Volume = ​4 x 10-10 x 1 = ​4 x 10-10 mol
```
one year ago
Vikas TU
13786 Points
```							Dear student Ksp refers to the solubility product constant. It refers to the equilibrium constant of a solid solid substance dissolving in aqueous solution. The more soluble a substance is the higher the Ksp of that given solid. so with that background knowledge, we can now proceed to the calculations;first write down the equation; Mg(OH)2  ⇒ Mg2+ + 2OH-                            Ksp= [Mg2+] [OH-]²                       4.0x10^-12= S x (2S)²     where S is solubility              therefore 4.0 x 10-12= 4S³                        4.0 x 10-12= 0.1(4S²)               S= 3.16 x 10^-6    hence concentration of NaOH= 2 x (3.16 x 10^-6)                                                  = 6.32 x 10^-6
```
one year ago
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