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Ionisation energy of +He is 19.6 x 18 10- J atom 1 - . The energy of the first stationary state (n = 1) of + 2 Li is

Ionisation energy of +He is 19.6 x 18 10- J atom 1 - . The energy of the first stationary state (n = 1) of + 2 Li
is

Grade:12

2 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
204-771_Sat Aug 16 00-11-58.jpg
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
Please find the solution to your problem below.
 
I.E.He+/I.E.Li2+ = (ZHe+2 x nLi2+2) / (ZLi2+2 x nHe+2) = (4 x 1) / (9 x 1) = 4/9
or, I.E.Li2+ = 9/4 x 19.6 x 10-18 J
                 = 4.41 x 10-17 J/atom
 
Hope it helps.
Thanks and regards,
Kushagra

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