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In Q4, how will we proceed after finding i from equation delta T=i*Kf*m . ??

4 years ago

Answers : (1)

Vikas TU
12273 Points
Okay let suppose U find out the i that is von’t hoff factor.
And also lets for sake we assume after solving we get something i = 5.
And also assume the complex be => Co3+ [(Cl)x (NH3)y]z- 
The dissociation would be:
 Co3+ [(Cl)x (NH3)y]z-        ------------>           zCo         + 3[(Cl)x (NH3)y]
As it is mentioned the ionisation is 100% then somehow,
i = z + 3
we have assumed  i = 7
z = 7 – 3 = > 4
hence -4 is the charge of [(Cl)x (NH3)y]
x * -1 + y*0 = -4
x = 4
hence no. of cl atoms is 4.
Note: I aave assumed i value u need to caluclate as u have mentioned that U have akready caluclated it. 
4 years ago
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