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`        in an elementary reaction A + 2B= 2C +D. if the conc of A is increased four times and B is decreased to half of its initial then the rate becomes ?`
one year ago

Arun
22558 Points
```							Dear Preeti Kp = [C]²[D]/ [A][B]² Now if concentration of A is increased by 4 times [A'] = [4A]and [B'] = [B/2]Hence new rate K'p = 4[C]²[D]/ 4[A][B]= Kpi.e. no change in rate of reaction. RegardsArun(askIITians forum expert)
```
one year ago
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• NCERT Solutions
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