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in an elementary reaction A + 2B= 2C +D. if the conc of A is increased four times and B is decreased to half of its initial then the rate becomes ?

Preeti , 8 Years ago
Grade 11
anser 1 Answers
Arun
Dear Preeti
 
Kp = [C]²[D]/ [A][B]²
 
Now if concentration of A is increased by 4 times 
[A'] = [4A]
and 
[B'] = [B/2]
Hence new rate 
K'p = 4[C]²[D]/ 4[A][B]
= Kp
i.e. no change in rate of reaction.
 
Regards
Arun(askIITians forum expert)
Last Activity: 8 Years ago
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