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If an endothermic reaction is non spontaneous at freezing point of water and becomes feasible at it's boiling point, then A. DeltaH is -ve, DeltaS is +be B. DeltaH and DeltaS both are +ve C. DeltaH and DeltaS both are -ve D. DeltaH is +ve, DeltaS is -ve Plz explain By shailwi

If an endothermic reaction is non spontaneous at freezing point of water and becomes feasible at it's boiling point, then
A. DeltaH is -ve, DeltaS is +be
B. DeltaH and DeltaS both are +ve
C. DeltaH and DeltaS both are -ve
D. DeltaH is +ve, DeltaS is -ve
Plz explain 
By shailwi

Grade:

1 Answers

Arun
25750 Points
5 years ago
For endothermic reaction, ΔH = +ve
Now, ΔG = ΔH – TΔS
For nonspontaneous
reaction, ΔG should be positive
Now ΔG is positive at low temperature if ΔH is positive.
ΔG is negative at high temperature if ΔS is positive.
 
Hence option B is correct.

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