If 3.01×10 20 molecules are removed from 98mg of H 2 SO 4 , then number of moles of H 2 SO 4 left will be?

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Arun · Answer

3.01 * 10 20 molecules = 3.01 * 10 20 /6.02 * 10 23 = 2 * 10 -3 moles 98 mg of H 2 SO 4 = 98 * 10 -2 /98 = 0.01 moles of H 2 SO 4 Thus when 0.002 moles are removed from 0.01 moles no. of moles left = 0.008 moles

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If 3.01×10 20 molecules are removed from 98mg of H 2 SO 4 , then number of moles of H 2 SO 4 left will be?

If 3.01×10²⁰ molecules are removed from 98mg of H₂SO₄, then number of moles of H₂SO₄ left will be?

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If 3.01×10 20 molecules are removed from 98mg of H 2 SO 4 , then number of moles of H 2 SO 4 left will be?

If 3.01×1020 molecules are removed from 98mg of H2SO4, then number of moles of H2SO4 left will be?

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If 3.01×10²⁰ molecules are removed from 98mg of H₂SO₄, then number of moles of H₂SO₄ left will be?