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Grade: upto college level
        he equivalent weight of MnSO4 is half of its molecular weight when it converts toa. Mn¬2O3

b. MnO2
c. 〖MnO〗_4^-
d. 〖MnO〗_4^(2-)
5 years ago

Answers : (2)

Deepak Patra
askIITians Faculty
471 Points
							Sol. Equivalent weight in redox system is defined as :
E= (Molar mass)/(n-factor)
Here n-factor is the net change in oxidation number per formula unit of oxidizing or reducing agent. In the present case-n-factor is 2 because equivalent weight is half of molecular weight. Also,
MnSO4 → 1/2 Mn2O3 1 (+ 2 → + 3)
MnSO4 → MnO2 2 (+ 2 → + 4)
MnSO4 → MnO_4^- 5 (+ 2 → + 7)
MnSO4 → MnO_4^(2-) 4 (+ 2 → + 6)
Therefore,MnSO4 converts to MnO2.

						
5 years ago
adi
23 Points
							
firstly guys we know that net oxidation state of Mn in MnSo4  is Mn+(SO4)=0
so,Mn+(-2)=0 (net charge of SO4=-2)
Mn=2
now net charge of Mn in MnO2=
Mn+(-2)2 (net charge on O=-2
Mn=4
MnSO4-----MnO2
equivalent weight =molecular weight (let M)/change in the oxidation state
equivalent weight=M/(4-2)
=M/2 
Thus equivalent weight of MnSO4 is half the molecular weight when it is converted to MnO2
4 years ago
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