ΔH>0 ΔS<0
This is the reverse of the previous case; the entropy increase must overcome the handicap of an endothermic process so thatTΔS> ΔH. Since the effect of the temperature is to "magnify" the influence of a positive ΔS, the process will be spontaneous at temperaturesaboveT= ΔH/ ΔS. (Think of melting and boiling.)