For a particular reversible reaction at temperature T, H ? and S ? were found to be both +ve. If eT is the
temperature at equilibrium, the reaction would be spontaneous when

Question

For a particular reversible reaction at temperature T, H ? and S ? were found to be both +ve. If eT is the temperature at equilibrium, the reaction would be spontaneous when

Sunil Kumar FP · Answer

&Delta;H>0 &Delta;S<0 This is the reverse of the previous case; the entropy increase must overcome the handicap of an endothermic process so thatT&Delta;S> &Delta;H. Since the effect of the temperature is to "magnify" the influence of a positive &Delta;S, the process will be spontaneous at temperaturesaboveT= &Delta;H/ &Delta;S. (Think of melting and boiling.)

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For a particular reversible reaction at temperature T, H ? and S ? were found to be both +ve. If eT is the temperature at equilibrium, the reaction would be spontaneous when

For a particular reversible reaction at temperature T, H ? and S ? were found to be both +ve. If eT is the
temperature at equilibrium, the reaction would be spontaneous when

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For a particular reversible reaction at temperature T, H ? and S ? were found to be both +ve. If eT is the temperature at equilibrium, the reaction would be spontaneous when

For a particular reversible reaction at temperature T, H ? and S ? were found to be both +ve. If eT is the temperature at equilibrium, the reaction would be spontaneous when

1 Answers

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For a particular reversible reaction at temperature T, H ? and S ? were found to be both +ve. If eT is the
temperature at equilibrium, the reaction would be spontaneous when