For a d-electron, the orbital angular momentum is
a. √6 (h/2π)
b. √2 (h/2π)
c. (h/2π)
d. 2 (h/2π)

Question

For a d-electron, the orbital angular momentum is a. √6 (h/2π) b. √2 (h/2π) c. (h/2π) d. 2 (h/2π)

Deepak Patra · Answer

The orbital angular momentum (L) = √(l (l+1)) h/2π = √6 h/2π (l = 2 for d-orbital)

Kushagra Madhukar · Answer

Dear student, Please find the attached solution to your solution. The orbital angular momentum (L) = √(l (l+1)) h/2π = √6h/2π (l = 2 for d-orbital) Hence option a) is correct. Hope it helps. Thanks and regards, Kushagra

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For a d-electron, the orbital angular momentum is a. √6 (h/2π) b. √2 (h/2π) c. (h/2π) d. 2 (h/2π)

For a d-electron, the orbital angular momentum is
a. √6 (h/2π)
b. √2 (h/2π)
c. (h/2π)
d. 2 (h/2π)

2 Answers

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For a d-electron, the orbital angular momentum is a. √6 (h/2π) b. √2 (h/2π) c. (h/2π) d. 2 (h/2π)

For a d-electron, the orbital angular momentum is a. √6 (h/2π) b. √2 (h/2π) c. (h/2π) d. 2 (h/2π)

2 Answers

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For a d-electron, the orbital angular momentum is
a. √6 (h/2π)
b. √2 (h/2π)
c. (h/2π)
d. 2 (h/2π)