badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

Flask 'A' of volume 10 L containing 20g of H2 and flask 'B' of volume 10 L containing 88 g of CO2 are connected by a connector having negligible volume. When the valve of the connector is opened, the number of moles of H2 remains in the flask 'A' is T(H2)=500k T(CO2)=200K

2 years ago

Answers : (1)

Shweta Ahire
44 Points
							
Initial moles of H2 in flask A = 10
Initial moles of CO2 in flask B = 2 
Total moles = 12 
After opening the connector ,  gases will mix then pressure of both of the flask changes but no of total moles be same
So p×10/R× 500  +  p×10/R × 200 = 12(total moles)
After solving this, p= 1200R/ 7
moles remaining in flask A =(1200R/7 × 10)/R ×500
= 24/7  =  3.428
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details