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```
find the percentage composition of 35Cl and 37Cl that amount for atomic masses of Cl 35.45

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3 years ago

```							The percent abundance of Cl-35 = 76.0%.Explanation:The percent abundance of chlorine-35 and chlorine-37 must equal 100, or, in decimal form 1.Given/Known:atomic weight of Cl-35 = 34.9689atomic weight of Cl-37 = 36.9695atomic weight of chlorine = 35.45Unknown:x = abundance of Cl-351-x = abundance of Cl-37SOLUTION:1. Set up the equation as follows:(34.9689)x + (36.9695)(1-x) = 35.452. Carry out multiplication.34.9689x + 36.9695 - 36.9695x = 35.453. Combine the x values.-2.0006x + 36.9695 = 35.454. Subtract 36.9695 from both sides.-2.0006x = - 1.52 (rounded to two decimal places due to significant figure rounding rules for addition and subtraction)5. Divide both sides by -2.0006 to calculate abundance.x = 0.760 (rounded to three significant figure due to rounding rules for multiplication and division)1 - 0.760 = 0.240 (In this case 1 is an exact number, which has an infinite number of significant figures, so significant figures are dependent upon 0.760, which has three decimal places.)6. Multiply abundance times 100 to get percent abundance.0.760 x 100 = 76.0%0.24 x 100 = 24.0%Answer:The percent abundance of Cl-35 = 76.0%.The percent abundance of Cl-37 = 24.0%.
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3 years ago
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