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Grade: 12th pass
        Equal moles of benzine and tolune are mixed the v.p of benzine and tolune in pure state are 700 and 600 mmHg respectively.the mole friction of benzine in vapour state is?
2 years ago

Answers : (1)

Arun
23742 Points
							
Suppose the moles of benzene and toluene are x.
Hence their mole fraction X=x/2x = ½
The vapour pressure of benzene in pure state P(a) =700 mm of Hg
The vapour pressure of toluene in pure state P(b) =600 mm of Hg
Now total pressure P (t) = P(a) X(a) + P(b) X(b)
                                            = 700 * ½  + 600 * ½
                                            =350 + 300
                                    P(t) = 650 mm of Hg
Now from Dalton’s law, P(a) X(a)=P(t) Y(a)         where Y(a)= mole fraction of benzene in vapour state
                                           700 * ½ = 650 * Y(a)
                                            Y(a) = 0.538 
2 years ago
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