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Density of 3M solution of NaCl is 1.252g ml^-1 the molality of solution is ?
molarity=no. of moles of solute /volume of solutionngiven molarity =3Mmeans, no of moles of solute =3 and volume of solution =1Ldensity =mass /volume 1.252=mass/1000 (1L=1000ml)mass of solution =1252gno. of moles of solute = mass (W)/molar mass(M)3=W/58.5 (NaCl= 23+35.5=58.5g/mol)W=175.5gmass of solvent =mass of solution-mass of solute mass of solvent =1252-175.5=1076.5gmolality =no. of mole of solute /mass of solvent in kg molality =3/1.076 =2.788
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