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De-broglie wavelength of electron is related to applied voltage is

Omnika , 6 Years ago
Grade 11
anser 2 Answers
Khimraj

Last Activity: 6 Years ago

λde Broglie=
h/p = h/me.ve =
since p2/2m = E = eV
so p = \sqrt{2meV}
so \lambda = h/\sqrt{2meV}
…............................................................

Khimraj

Last Activity: 6 Years ago

\lambda = h/p
p2/2m = E = eV
so p = \sqrt{2meV}
so \lambda  = h/\sqrt{2meV}
Hope it clears........................................................................................................

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